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10x^2+8x-66=0
a = 10; b = 8; c = -66;
Δ = b2-4ac
Δ = 82-4·10·(-66)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-52}{2*10}=\frac{-60}{20} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+52}{2*10}=\frac{44}{20} =2+1/5 $
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